What is the answer to ln((x^2)/(x+2))=0 ?

The answer to ln((x^2)/(x+2))=0 is x=2,x=-1

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ln((x^2)/(x+2))=0

ln (\frac{x ^{2}}{x + 2}) = 0

x = 2, x = - 1

Solution steps

ln (\frac{x ^{2}}{x + 2}) = 0

Apply log rules

\frac{x ^{2}}{x + 2} = e^{0}

Multiply both sides by

x + 2

\frac{x ^{2}}{x + 2} (x + 2) = e^{0} (x + 2)

Simplify

x^{2} = x + 2

Solve

x^{2} = x + 2 : x = 2, x = - 1

x = 2, x = - 1

Verify Solutions:

x = 2

True

, x = - 1

True

The solutions are

x = 2, x = - 1

lo g_{2} (x + 5) = - lo g_{2} (x + 3) + 3

- 0.04 = lo g_{10} (x)

lo g_{3} (x) - 2 lo g_{10} (x) (3) = 1

lo g_{10} (x) = 22.2

29728 = - 1.987 (298) ln (x)

What is the answer to ln((x^2)/(x+2))=0 ?
The answer to ln((x^2)/(x+2))=0 is x=2,x=-1
Solve for x: ln((x^2)/(x+2))=0
The solution is x=2,x=-1