What is the answer to log_{3}(2)+log_{3}(x-4)=1 ?

The answer to log_{3}(2)+log_{3}(x-4)=1 is x= 11/2

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log_{3}(2)+log_{3}(x-4)=1

lo g_{3} (2) + lo g_{3} (x - 4) = 1

x = \frac{11}{2}

Decimal Notation

x = 5.5

Solution steps

lo g_{3} (2) + lo g_{3} (x - 4) = 1

Move

lo g_{3} (2)

to the right side

lo g_{3} (x - 4) = 1 - lo g_{3} (2)

Apply log rules

x - 4 = \frac{3}{2}

Solve

x - 4 = \frac{3}{2} : x = \frac{11}{2}

x = \frac{11}{2}

Verify Solutions:

x = \frac{11}{2}

True

The solution is

x = \frac{11}{2}

ln (x) = 51208

ln (x) (2 ln (x) + 1) = 2

lo g_{2} (n) = 2

lo g_{e} (7 x - 3) = x + 9

lo g_{3} (x + 1) - lo g_{3} (2 - x) = 1

What is the answer to log_{3}(2)+log_{3}(x-4)=1 ?
The answer to log_{3}(2)+log_{3}(x-4)=1 is x= 11/2
Solve for x: log_{3}(2)+log_{3}(x-4)=1
The solution is x= 11/2