What is the answer to log_{2}(n)=sqrt(2) ?

The answer to log_{2}(n)=sqrt(2) is n=2^{sqrt(2)}

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log_{2}(n)=sqrt(2)

lo g_{2} (n) = 2

n = 2^{2}

Decimal Notation

n = 2.66514 \dots

Solution steps

lo g_{2} (n) = 2

Apply log rules

n = 2^{2}

lo g_{e} (7 x - 3) = x + 9

lo g_{3} (x + 1) - lo g_{3} (2 - x) = 1

4 lo g_{9} (x) = 0

lo g_{2} (n) = 3

- lo g_{10} (x) = 4.3

What is the answer to log_{2}(n)=sqrt(2) ?
The answer to log_{2}(n)=sqrt(2) is n=2^{sqrt(2)}
Solve for n: log_{2}(n)=sqrt(2)
The solution is n=2^{sqrt(2)}