What is the answer to log_{2}(n)=sqrt(3) ?

The answer to log_{2}(n)=sqrt(3) is n=2^{sqrt(3)}

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log_{2}(n)=sqrt(3)

lo g_{2} (n) = 3

n = 2^{3}

Decimal Notation

n = 3.32199 \dots

Solution steps

lo g_{2} (n) = 3

Apply log rules

n = 2^{3}

- lo g_{10} (x) = 4.3

lo g_{3} (4 x) = lo g_{6} (x)

lo g_{3} (x + 7) = lo g_{3} (x - 1) + 2

lo g_{3} (x) - lo g_{x} (9) = 0

ln (T) = 1.56 + 0.82 \cdot ln (56)

What is the answer to log_{2}(n)=sqrt(3) ?
The answer to log_{2}(n)=sqrt(3) is n=2^{sqrt(3)}
Solve for n: log_{2}(n)=sqrt(3)
The solution is n=2^{sqrt(3)}