What is the answer to log_{3}(x+7)=log_{3}(x-1)+2 ?

The answer to log_{3}(x+7)=log_{3}(x-1)+2 is x=2

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log_{3}(x+7)=log_{3}(x-1)+2

lo g_{3} (x + 7) = lo g_{3} (x - 1) + 2

x = 2

Solution steps

lo g_{3} (x + 7) = lo g_{3} (x - 1) + 2

Apply log rules

x + 7 = (x - 1) \cdot 9

Solve

x + 7 = (x - 1) \cdot 9 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

lo g_{3} (x) - lo g_{x} (9) = 0

ln (T) = 1.56 + 0.82 \cdot ln (56)

lo g_{10} (5 k) = 10

- 6 = - ln ((0)^{2} + c_{1})

lo g_{3 x + 2} (8) = lo g_{5} (2)

What is the answer to log_{3}(x+7)=log_{3}(x-1)+2 ?
The answer to log_{3}(x+7)=log_{3}(x-1)+2 is x=2
Solve for x: log_{3}(x+7)=log_{3}(x-1)+2
The solution is x=2