What is the answer to log_{4}(x+5)-log_{4}(x-5)=2 ?

The answer to log_{4}(x+5)-log_{4}(x-5)=2 is x= 17/3

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log_{4}(x+5)-log_{4}(x-5)=2

lo g_{4} (x + 5) - lo g_{4} (x - 5) = 2

x = \frac{17}{3}

Solution steps

lo g_{4} (x + 5) - lo g_{4} (x - 5) = 2

Add

lo g_{4} (x - 5)

to both sides

lo g_{4} (x + 5) - lo g_{4} (x - 5) + lo g_{4} (x - 5) = 2 + lo g_{4} (x - 5)

Simplify

lo g_{4} (x + 5) = 2 + lo g_{4} (x - 5)

Apply log rules

x + 5 = 16 (x - 5)

Solve

x + 5 = 16 (x - 5) : x = \frac{17}{3}

x = \frac{17}{3}

Verify Solutions:

x = \frac{17}{3}

True

The solution is

x = \frac{17}{3}

2 \cdot x^{1 + l o g_{2} (x)} = x^{3}

x, e^{2} = ln (x)

- 2 = ln ∣ x ∣

ln (x + 8) + ln (10) = 3

x, f x = ln (14 x)

What is the answer to log_{4}(x+5)-log_{4}(x-5)=2 ?
The answer to log_{4}(x+5)-log_{4}(x-5)=2 is x= 17/3
Solve for x: log_{4}(x+5)-log_{4}(x-5)=2
The solution is x= 17/3