What is the answer to log_{2}(2x^2+10x+16)=2 ?

The answer to log_{2}(2x^2+10x+16)=2 is x=-2,x=-3

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log_{2}(2x^2+10x+16)=2

lo g_{2} (2 x^{2} + 10 x + 16) = 2

x = - 2, x = - 3

Solution steps

lo g_{2} (2 x^{2} + 10 x + 16) = 2

Apply log rules

2 x^{2} + 10 x + 16 = 4

Solve

2 x^{2} + 10 x + 16 = 4 : x = - 2, x = - 3

x = - 2, x = - 3

3 lo g_{9} (3) = lo g_{9} (x)

lo g_{64} (x) = \frac{2}{6}

9 + 6 ln (x) = 6

- lo g_{10} (x) = 3.4

45 = 20 + 47 lo g_{10} (x + 2)

What is the answer to log_{2}(2x^2+10x+16)=2 ?
The answer to log_{2}(2x^2+10x+16)=2 is x=-2,x=-3
Solve for x: log_{2}(2x^2+10x+16)=2
The solution is x=-2,x=-3