What is the answer to log_{2}(x+7)+log_{2}(x-5)=6 ?

The answer to log_{2}(x+7)+log_{2}(x-5)=6 is x=9

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log_{2}(x+7)+log_{2}(x-5)=6

lo g_{2} (x + 7) + lo g_{2} (x - 5) = 6

x = 9

Solution steps

lo g_{2} (x + 7) + lo g_{2} (x - 5) = 6

Apply log rules

(x + 7) (x - 5) = 64

Solve

(x + 7) (x - 5) = 64 : x = 9, x = - 11

x = 9, x = - 11

Verify Solutions:

x = 9

True

, x = - 11

False

The solution is

x = 9

lo g_{9} (64 - x^{2}) = 1

- 3 ln (x + 2) = 0

lo g_{e} (6 - 8 x) = - 2

- 3 ln (x + 2) = 6

lo g_{5} (3 x^{2} + 7 x + 3) = 0

What is the answer to log_{2}(x+7)+log_{2}(x-5)=6 ?
The answer to log_{2}(x+7)+log_{2}(x-5)=6 is x=9
Solve for x: log_{2}(x+7)+log_{2}(x-5)=6
The solution is x=9