What is the answer to log_{9}(64-x^2)=1 ?

The answer to log_{9}(64-x^2)=1 is x=sqrt(55),x=-sqrt(55)

Solve for x: log_{9}(64-x^2)=1

The solution is x=sqrt(55),x=-sqrt(55)

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lo g_{9} (64 - x^{2}) = 1

x = 55, x = - 55

Decimal Notation

x = 7.41619 \dots, x = - 7.41619 \dots

Solution steps

lo g_{9} (64 - x^{2}) = 1

Apply log rules

64 - x^{2} = 9

Solve

64 - x^{2} = 9 : x = 55, x = - 55

x = 55, x = - 55

- 3 ln (x + 2) = 0

lo g_{e} (6 - 8 x) = - 2

- 3 ln (x + 2) = 6

lo g_{5} (3 x^{2} + 7 x + 3) = 0

ln (x - 1) + ln (x - 2) = ln (7)

What is the answer to log_{9}(64-x^2)=1 ?
The answer to log_{9}(64-x^2)=1 is x=sqrt(55),x=-sqrt(55)
Solve for x: log_{9}(64-x^2)=1
The solution is x=sqrt(55),x=-sqrt(55)