What is the answer to log_{5}(t^2+6t)=log_{5}(7) ?

The answer to log_{5}(t^2+6t)=log_{5}(7) is t=1,t=-7

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log_{5}(t^2+6t)=log_{5}(7)

lo g_{5} (t^{2} + 6 t) = lo g_{5} (7)

t = 1, t = - 7

Solution steps

lo g_{5} (t^{2} + 6 t) = lo g_{5} (7)

Apply log rules

t^{2} + 6 t = 7

Solve

t^{2} + 6 t = 7 : t = 1, t = - 7

t = 1, t = - 7

Verify Solutions:

t = 1

True

, t = - 7

True

The solutions are

t = 1, t = - 7

ln (4 t) - ln (3 t) = 2

lo g_{10} (m) = - 1 + lo g_{10} (m + 3)

lo g_{2} (4 x + 5) - lo g_{2} (4 - x) = 3

ln (x) = ln^{2} (x)

lo g_{6} (5 x) = 3

What is the answer to log_{5}(t^2+6t)=log_{5}(7) ?
The answer to log_{5}(t^2+6t)=log_{5}(7) is t=1,t=-7
Solve for t: log_{5}(t^2+6t)=log_{5}(7)
The solution is t=1,t=-7