What is the answer to 2ln(3x)+ln(x-1)=0 ?

The answer to 2ln(3x)+ln(x-1)=0 is x\approx 1.09300…

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2ln(3x)+ln(x-1)=0

2 ln (3 x) + ln (x - 1) = 0

x \approx 1.09300 \dots

Solution steps

2 ln (3 x) + ln (x - 1) = 0

Apply log rules

9 x^{2} (x - 1) = 1

Solve

9 x^{2} (x - 1) = 1 : x \approx 1.09300 \dots

x \approx 1.09300 \dots

Verify Solutions:

x \approx 1.09300 \dots

True

The solution is

x \approx 1.09300 \dots

86 = 20 lo g_{10} (\frac{x}{20})

x, t = 5 ln (x)

ln (3 x^{2} - 2 x) = 0

lo g_{a} (6) = 0.1436

x, 0.72 = lo g_{10} (x)

What is the answer to 2ln(3x)+ln(x-1)=0 ?
The answer to 2ln(3x)+ln(x-1)=0 is x\approx 1.09300…
Solve for x: 2ln(3x)+ln(x-1)=0
The solution is x\approx 1.09300…