What is the answer to ln(3x^2-2x)=0 ?

The answer to ln(3x^2-2x)=0 is x=1,x=-1/3

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ln(3x^2-2x)=0

ln (3 x^{2} - 2 x) = 0

x = 1, x = - \frac{1}{3}

Decimal Notation

x = 1, x = - 0.33333 \dots

Solution steps

ln (3 x^{2} - 2 x) = 0

Apply log rules

3 x^{2} - 2 x = 1

Solve

3 x^{2} - 2 x = 1 : x = 1, x = - \frac{1}{3}

x = 1, x = - \frac{1}{3}

lo g_{a} (6) = 0.1436

x, 0.72 = lo g_{10} (x)

2 lo g_{10} (x) + 4 = 10

ln (x + 11) + ln (x - 3) = 2 ln (x)