What is the answer to ln(x+11)+ln(x-3)=2ln(x) ?

The answer to ln(x+11)+ln(x-3)=2ln(x) is x= 33/8

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ln(x+11)+ln(x-3)=2ln(x)

ln (x + 11) + ln (x - 3) = 2 ln (x)

x = \frac{33}{8}

Solution steps

ln (x + 11) + ln (x - 3) = 2 ln (x)

Apply log rules

(x + 11) (x - 3) = x^{2}

Solve

(x + 11) (x - 3) = x^{2} : x = \frac{33}{8}

x = \frac{33}{8}

Verify Solutions:

x = \frac{33}{8}

True

The solution is

x = \frac{33}{8}

lo g_{5} (10 b + 10) = lo g_{5} (50)

ln (- x) = - 1 π

lo g_{25} (x + 1) = \frac{1}{2}

lo g_{b} (0) = 1

lo g_{3} (x^{2} + 1) = lo g_{3} (10)

What is the answer to ln(x+11)+ln(x-3)=2ln(x) ?
The answer to ln(x+11)+ln(x-3)=2ln(x) is x= 33/8
Solve for x: ln(x+11)+ln(x-3)=2ln(x)
The solution is x= 33/8