What is the answer to log_{3}(x^2+1)=log_{3}(10) ?

The answer to log_{3}(x^2+1)=log_{3}(10) is x=3,x=-3

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log_{3}(x^2+1)=log_{3}(10)

lo g_{3} (x^{2} + 1) = lo g_{3} (10)

x = 3, x = - 3

Solution steps

lo g_{3} (x^{2} + 1) = lo g_{3} (10)

Apply log rules

x^{2} + 1 = 10

Solve

x^{2} + 1 = 10 : x = 3, x = - 3

x = 3, x = - 3

Verify Solutions:

x = 3

True

, x = - 3

True

The solutions are

x = 3, x = - 3

ln (2 x) = 1.5

y, lo g_{6} (y) = x

ln (1 - 2 y) = 0

0 = - 2 lo g_{9} (3 x) + 1

lo g_{x} (x) - 1 + lo g_{x} (x - 2) = 2

What is the answer to log_{3}(x^2+1)=log_{3}(10) ?
The answer to log_{3}(x^2+1)=log_{3}(10) is x=3,x=-3
Solve for x: log_{3}(x^2+1)=log_{3}(10)
The solution is x=3,x=-3