What is the answer to log_{10}(3)+log_{10}(x)=23 ?

The answer to log_{10}(3)+log_{10}(x)=23 is x=(10^{23})/3

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log_{10}(3)+log_{10}(x)=23

lo g_{10} (3) + lo g_{10} (x) = 23

x = \frac{1 0 ^{23}}{3}

Decimal Notation

x = 3.33333 E 22

Solution steps

lo g_{10} (3) + lo g_{10} (x) = 23

Move

lo g_{10} (3)

to the right side

lo g_{10} (x) = 23 - lo g_{10} (3)

Apply log rules

x = \frac{1 0 ^{23}}{3}

Verify Solutions:

x = \frac{1 0 ^{23}}{3}

True

The solution is

x = \frac{1 0 ^{23}}{3}

lo g_{2} (5 x) - 3 lo g_{x} (7) = 0

lo g_{2} (x + 5) - lo g_{2} (x - 1) = 5

6 (ln (4 x - 9)) + 14 = 26

3.1 = - lo g_{10} (x)

x, 6.07 = - lo g_{10} (x)

What is the answer to log_{10}(3)+log_{10}(x)=23 ?
The answer to log_{10}(3)+log_{10}(x)=23 is x=(10^{23})/3
Solve for x: log_{10}(3)+log_{10}(x)=23
The solution is x=(10^{23})/3