What is the answer to 3.1=-log_{10}(x) ?

The answer to 3.1=-log_{10}(x) is x= 1/(10^{3.1)}

Solve for x: 3.1=-log_{10}(x)

The solution is x= 1/(10^{3.1)}

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3.1 = - lo g_{10} (x)

x = \frac{1}{1 0 ^{3.1}}

Solution steps

3.1 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

3.1 + lo g_{10} (x) = 0

Move

3.1

to the right side

lo g_{10} (x) = - 3.1

Apply log rules

x = \frac{1}{1 0 ^{3.1}}

Verify Solutions:

x = \frac{1}{1 0 ^{3.1}}

True

The solution is

x = \frac{1}{1 0 ^{3.1}}

x, 6.07 = - lo g_{10} (x)

lo g_{5} (- 7 - 5 x) = 2

lo g_{1} (x - 1) = 5

lo g_{7} (x) - lo g_{7} (3) = 2

lo g_{3} (x) + lo g_{3} (10) = 2

What is the answer to 3.1=-log_{10}(x) ?
The answer to 3.1=-log_{10}(x) is x= 1/(10^{3.1)}
Solve for x: 3.1=-log_{10}(x)
The solution is x= 1/(10^{3.1)}