What is the answer to log_{5}(-7-5x)=2 ?

The answer to log_{5}(-7-5x)=2 is x=-32/5

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log_{5}(-7-5x)=2

lo g_{5} (- 7 - 5 x) = 2

x = - \frac{32}{5}

Solution steps

lo g_{5} (- 7 - 5 x) = 2

Apply log rules

- 7 - 5 x = 25

Solve

- 7 - 5 x = 25 : x = - \frac{32}{5}

x = - \frac{32}{5}

lo g_{1} (x - 1) = 5

lo g_{7} (x) - lo g_{7} (3) = 2

lo g_{3} (x) + lo g_{3} (10) = 2

2 lo g_{8} (3 y - 5) + 20 = 24

9.21 = - lo g_{10} (x)

What is the answer to log_{5}(-7-5x)=2 ?
The answer to log_{5}(-7-5x)=2 is x=-32/5
Solve for x: log_{5}(-7-5x)=2
The solution is x=-32/5