What is the answer to log_{3}(x)+log_{3}(10)=2 ?

The answer to log_{3}(x)+log_{3}(10)=2 is x= 9/10

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log_{3}(x)+log_{3}(10)=2

lo g_{3} (x) + lo g_{3} (10) = 2

x = \frac{9}{10}

Solution steps

lo g_{3} (x) + lo g_{3} (10) = 2

Move

lo g_{3} (10)

to the right side

lo g_{3} (x) = 2 - lo g_{3} (10)

Apply log rules

x = \frac{9}{10}

Verify Solutions:

x = \frac{9}{10}

True

The solution is

x = \frac{9}{10}

2 lo g_{8} (3 y - 5) + 20 = 24

9.21 = - lo g_{10} (x)

- lo g_{10} (T) = 0.064

lo g_{4} (x - 5) + lo g_{4} (x + 3) = 1

lo g_{10} (200) = 4 - 3 lo g_{10} (x)

What is the answer to log_{3}(x)+log_{3}(10)=2 ?
The answer to log_{3}(x)+log_{3}(10)=2 is x= 9/10
Solve for x: log_{3}(x)+log_{3}(10)=2
The solution is x= 9/10