What is the answer to ln(r)+ln(10)= 3/2 ?

The answer to ln(r)+ln(10)= 3/2 is r=(e^{3/2})/(10)

Solve for r: ln(r)+ln(10)= 3/2

The solution is r=(e^{3/2})/(10)

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ln (r) + ln (10) = \frac{3}{2}

r = \frac{e ^{\frac{3}{2}}}{10}

Solution steps

ln (r) + ln (10) = \frac{3}{2}

Move

ln (10)

to the right side

ln (r) = \frac{3}{2} - ln (10)

Apply log rules

r = \frac{e ^{\frac{3}{2}}}{10}

Verify Solutions:

r = \frac{e ^{\frac{3}{2}}}{10}

True

The solution is

r = \frac{e ^{\frac{3}{2}}}{10}

2 ln (x + 1) + 1 = 0

lo g_{3} (8 x - 15) = 4

x^{2} y - 2 x y^{2} + ln (x) y = x y

lo g_{8} (a) = lo g_{2} (x), x > 0

lo g_{x} (3) = 0.4771

What is the answer to ln(r)+ln(10)= 3/2 ?
The answer to ln(r)+ln(10)= 3/2 is r=(e^{3/2})/(10)
Solve for r: ln(r)+ln(10)= 3/2
The solution is r=(e^{3/2})/(10)