What is the answer to 2log_{5}(x)+log_{10}(x)=2 ?

The answer to 2log_{5}(x)+log_{10}(x)=2 is x=10^{(2log_{10}(5))/(2+log_{10)(5)}}

Solve for x: 2log_{5}(x)+log_{10}(x)=2

The solution is x=10^{(2log_{10}(5))/(2+log_{10)(5)}}

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2 lo g_{5} (x) + lo g_{10} (x) = 2

x = 1 0^{\frac{2 l o g _{10} ( 5 )}{2 + l o g _{10} ( 5 )}}

Solution steps

2 lo g_{5} (x) + lo g_{10} (x) = 2

Apply log rules

x = 1 0^{\frac{2 l o g _{10} ( 5 )}{2 + l o g _{10} ( 5 )}}

Verify Solutions:

x = 1 0^{\frac{2 l o g _{10} ( 5 )}{2 + l o g _{10} ( 5 )}}

True

The solution is

x = 1 0^{\frac{2 l o g _{10} ( 5 )}{2 + l o g _{10} ( 5 )}}

x, 7 ln (2 x + 3) - 40 = 9

ln (x) + x = 2

2 lo g_{x} (2) + 4 lo g_{x} (4) = 5

\frac{x}{ln ( x )} = 1

6 ln (7 x - 8) + 8 = 50

What is the answer to 2log_{5}(x)+log_{10}(x)=2 ?
The answer to 2log_{5}(x)+log_{10}(x)=2 is x=10^{(2log_{10}(5))/(2+log_{10)(5)}}
Solve for x: 2log_{5}(x)+log_{10}(x)=2
The solution is x=10^{(2log_{10}(5))/(2+log_{10)(5)}}