What is the answer to -1.25ln(10-0.8x)+1.4539=3 ?

The answer to -1.25ln(10-0.8x)+1.4539=3 is x=(-1+10e^{\frac{1.5461)/(1.25)}}{0.8e^{(1.5461)/(1.25)}}

Solve for x: -1.25ln(10-0.8x)+1.4539=3

The solution is x=(-1+10e^{\frac{1.5461)/(1.25)}}{0.8e^{(1.5461)/(1.25)}}

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- 1.25 ln (10 - 0.8 x) + 1.4539 = 3

x = \frac{- 1 + 10 e ^{\frac{1.5461}{1.25}}}{0.8 e ^{\frac{1.5461}{1.25}}}

Decimal Notation

x = 12.13713 \dots

Solution steps

- 1.25 ln (10 - 0.8 x) + 1.4539 = 3

Move

1.4539

to the right side

- 1.25 ln (10 - 0.8 x) = 1.5461

Divide both sides by

- 1.25

ln (10 - 0.8 x) = - \frac{1.5461}{1.25}

Apply log rules

10 - 0.8 x = \frac{1}{e ^{\frac{1.5461}{1.25}}}

Solve

10 - 0.8 x = \frac{1}{e ^{\frac{1.5461}{1.25}}} : x = \frac{- 1 + 10 e ^{\frac{1.5461}{1.25}}}{0.8 e ^{\frac{1.5461}{1.25}}}

x = \frac{- 1 + 10 e ^{\frac{1.5461}{1.25}}}{0.8 e ^{\frac{1.5461}{1.25}}}

Verify Solutions:

x = \frac{- 1 + 10 e ^{\frac{1.5461}{1.25}}}{0.8 e ^{\frac{1.5461}{1.25}}}

True

The solution is

x = \frac{- 1 + 10 e ^{\frac{1.5461}{1.25}}}{0.8 e ^{\frac{1.5461}{1.25}}}

ln (8 w - 6) = ln (6 w)

0 = 20 lo g_{10} (3 x)

b, lo g_{b} (2) = 0.401

4 ln (x - 5) = - 4

0.172 = 2 - lo g_{10} (x)

What is the answer to -1.25ln(10-0.8x)+1.4539=3 ?
The answer to -1.25ln(10-0.8x)+1.4539=3 is x=(-1+10e^{\frac{1.5461)/(1.25)}}{0.8e^{(1.5461)/(1.25)}}
Solve for x: -1.25ln(10-0.8x)+1.4539=3
The solution is x=(-1+10e^{\frac{1.5461)/(1.25)}}{0.8e^{(1.5461)/(1.25)}}