What is the answer to ln(x)+ln(2x)=7 ?

The answer to ln(x)+ln(2x)=7 is x=e^{(7-ln(2))/2}

Solve for x: ln(x)+ln(2x)=7

The solution is x=e^{(7-ln(2))/2}

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ln (x) + ln (2 x) = 7

x = e^{\frac{7 - l n ( 2 )}{2}}

Decimal Notation

x = 23.41616 \dots

Solution steps

ln (x) + ln (2 x) = 7

Apply log rules

x = e^{\frac{7 - l n ( 2 )}{2}}

Verify Solutions:

x = e^{\frac{7 - l n ( 2 )}{2}}

True

The solution is

x = e^{\frac{7 - l n ( 2 )}{2}}

lo g_{7} (x + 6) = 2

lo g_{3} (12 x) - 3 = lo g_{2} (540)

x = e^{l o g_{7} (x)}

y, ln (1 - y) = - k t

\frac{1}{64} = lo g_{8} (x)

What is the answer to ln(x)+ln(2x)=7 ?
The answer to ln(x)+ln(2x)=7 is x=e^{(7-ln(2))/2}
Solve for x: ln(x)+ln(2x)=7
The solution is x=e^{(7-ln(2))/2}