What is the answer to log_{10}(x^2-3x+6)=1 ?

The answer to log_{10}(x^2-3x+6)=1 is x=4,x=-1

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log_{10}(x^2-3x+6)=1

lo g_{10} (x^{2} - 3 x + 6) = 1

x = 4, x = - 1

Solution steps

lo g_{10} (x^{2} - 3 x + 6) = 1

Apply log rules

x^{2} - 3 x + 6 = 10

Solve

x^{2} - 3 x + 6 = 10 : x = 4, x = - 1

x = 4, x = - 1

- 80 = 10 \cdot lo g_{10} (x)

1 + 2 lo g_{1} (x) - lo g_{1} (x + 2) = 0

x, 6.69 = - lo g_{10} (x)

0 = - 2 lo g_{9} (3 x + 1)

lo g_{10} (4 x - 10) = lo g_{10} (2 x)

What is the answer to log_{10}(x^2-3x+6)=1 ?
The answer to log_{10}(x^2-3x+6)=1 is x=4,x=-1
Solve for x: log_{10}(x^2-3x+6)=1
The solution is x=4,x=-1