What is the answer to 1+2log_{1}(x)-log_{1}(x+2)=0 ?

The answer to 1+2log_{1}(x)-log_{1}(x+2)=0 is No Solution for x\in\mathbb{R}

Solve for x: 1+2log_{1}(x)-log_{1}(x+2)=0

The solution is No Solution for x\in\mathbb{R}

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1 + 2 lo g_{1} (x) - lo g_{1} (x + 2) = 0

No Solution for x \in R

Solution steps

1 + 2 lo g_{1} (x) - lo g_{1} (x + 2) = 0

lo g_{1} (a)

is undefined

No Solution for x \in R

x, 6.69 = - lo g_{10} (x)

0 = - 2 lo g_{9} (3 x + 1)

lo g_{10} (4 x - 10) = lo g_{10} (2 x)

lo g_{x} (x^{2} + x - 6) = 1

10 lo g_{10} (x) = 0.17

What is the answer to 1+2log_{1}(x)-log_{1}(x+2)=0 ?
The answer to 1+2log_{1}(x)-log_{1}(x+2)=0 is No Solution for x\in\mathbb{R}
Solve for x: 1+2log_{1}(x)-log_{1}(x+2)=0
The solution is No Solution for x\in\mathbb{R}