What is the answer to x=9+ln(x) ?

The answer to x=9+ln(x) is x=-\W_{-1}(-1/(e^9)),x=-\W_{0}(-1/(e^9))

Solve for x: x=9+ln(x)

The solution is x=-\W_{-1}(-1/(e^9)),x=-\W_{0}(-1/(e^9))

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x = 9 + ln (x)

x = - W_{- 1} (- \frac{1}{e ^{9}}), x = - W_{0} (- \frac{1}{e ^{9}})

Decimal Notation

x = 11.43683 \dots, x = 0.00012 \dots

Solution steps

x = 9 + ln (x)

Switch sides

9 + ln (x) = x

Move

9

to the right side

ln (x) = x - 9

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x)} = e^{x - 9}

Simplify

e^{l n (x)} : x

x = e^{x - 9}

Solve

x = e^{x - 9} : x = - W_{- 1} (- \frac{1}{e ^{9}}), x = - W_{0} (- \frac{1}{e ^{9}})

x = - W_{- 1} (- \frac{1}{e ^{9}}), x = - W_{0} (- \frac{1}{e ^{9}})

Verify Solutions:

x = - W_{- 1} (- \frac{1}{e ^{9}})

True

, x = - W_{0} (- \frac{1}{e ^{9}})

True

The solutions are

x = - W_{- 1} (- \frac{1}{e ^{9}}), x = - W_{0} (- \frac{1}{e ^{9}})

lo g_{x} (3) = lo g_{2} (x)

x, lo g_{10} (x + 1) = 5

lo g_{7} (x) = lo g_{7} (20)

lo g_{4} (x^{2} + 60) = 2

2.12 = - lo g_{10} (x)

What is the answer to x=9+ln(x) ?
The answer to x=9+ln(x) is x=-\W_{-1}(-1/(e^9)),x=-\W_{0}(-1/(e^9))
Solve for x: x=9+ln(x)
The solution is x=-\W_{-1}(-1/(e^9)),x=-\W_{0}(-1/(e^9))