What is the answer to 0=-2log_{9}(3x+1) ?

The answer to 0=-2log_{9}(3x+1) is x=0

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0=-2log_{9}(3x+1)

0 = - 2 lo g_{9} (3 x + 1)

x = 0

Solution steps

0 = - 2 lo g_{9} (3 x + 1)

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

lo g_{9} (3 x + 1) = 0

Solve

lo g_{9} (3 x + 1) = 0 : x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

lo g_{10} (4 x - 10) = lo g_{10} (2 x)

lo g_{x} (x^{2} + x - 6) = 1

10 lo g_{10} (x) = 0.17

40 = 6 \cdot lo g_{2} (x)

x = 9 + ln (x)

What is the answer to 0=-2log_{9}(3x+1) ?
The answer to 0=-2log_{9}(3x+1) is x=0
Solve for x: 0=-2log_{9}(3x+1)
The solution is x=0