What is the answer to log_{6}((x+3)(x-2))=2 ?

The answer to log_{6}((x+3)(x-2))=2 is x=6,x=-7

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log_{6}((x+3)(x-2))=2

lo g_{6} ((x + 3) (x - 2)) = 2

x = 6, x = - 7

Solution steps

lo g_{6} ((x + 3) (x - 2)) = 2

Apply log rules

(x + 3) (x - 2) = 36

Solve

(x + 3) (x - 2) = 36 : x = 6, x = - 7

x = 6, x = - 7

lo g_{7} (x^{4}) = 4 lo g_{7} (x)

x, 3 - ln (- 2 - x) = 0

lo g_{4} (x - 2) = 2

lo g_{4} (x - 2) = 0

lo g_{2} (x + 1) + lo g_{2} (5) = 1

What is the answer to log_{6}((x+3)(x-2))=2 ?
The answer to log_{6}((x+3)(x-2))=2 is x=6,x=-7
Solve for x: log_{6}((x+3)(x-2))=2
The solution is x=6,x=-7