What is the answer to log_{2}(x+1)+log_{2}(5)=1 ?

The answer to log_{2}(x+1)+log_{2}(5)=1 is x=-3/5

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log_{2}(x+1)+log_{2}(5)=1

lo g_{2} (x + 1) + lo g_{2} (5) = 1

x = - \frac{3}{5}

Solution steps

lo g_{2} (x + 1) + lo g_{2} (5) = 1

Move

lo g_{2} (5)

to the right side

lo g_{2} (x + 1) = 1 - lo g_{2} (5)

Apply log rules

x + 1 = \frac{2}{5}

Solve

x + 1 = \frac{2}{5} : x = - \frac{3}{5}

x = - \frac{3}{5}

Verify Solutions:

x = - \frac{3}{5}

True

The solution is

x = - \frac{3}{5}

ln (x) = 5.116157985

lo g_{2} (x + 1) = 3 - lo g_{2} (x - 1)

lo g_{10} (x) = - 16

3 lo g_{10} (x + 1) = 2

s, x = lo g_{10} (s - 4)

What is the answer to log_{2}(x+1)+log_{2}(5)=1 ?
The answer to log_{2}(x+1)+log_{2}(5)=1 is x=-3/5
Solve for x: log_{2}(x+1)+log_{2}(5)=1
The solution is x=-3/5