What is the answer to 3log_{10}(x+1)=2 ?

The answer to 3log_{10}(x+1)=2 is x=10^{2/3}-1

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3log_{10}(x+1)=2

3 lo g_{10} (x + 1) = 2

x = 1 0^{\frac{2}{3}} - 1

Solution steps

3 lo g_{10} (x + 1) = 2

Divide both sides by

3

lo g_{10} (x + 1) = \frac{2}{3}

Apply log rules

x + 1 = 1 0^{\frac{2}{3}}

Solve

x + 1 = 1 0^{\frac{2}{3}} : x = 1 0^{\frac{2}{3}} - 1

x = 1 0^{\frac{2}{3}} - 1

Verify Solutions:

x = 1 0^{\frac{2}{3}} - 1

True

The solution is

x = 1 0^{\frac{2}{3}} - 1

s, x = lo g_{10} (s - 4)

0.78 = ln (x)

lo g_{2} (x^{2} - x - 9) = 2

0 = lo g_{10} (3 - 2 x)

lo g_{10} (x) = - 1.4886

What is the answer to 3log_{10}(x+1)=2 ?
The answer to 3log_{10}(x+1)=2 is x=10^{2/3}-1
Solve for x: 3log_{10}(x+1)=2
The solution is x=10^{2/3}-1