What is the answer to log_{2}(x^2-x-9)=2 ?

The answer to log_{2}(x^2-x-9)=2 is x=(1+sqrt(53))/2 ,x=(1-sqrt(53))/2

Solve for x: log_{2}(x^2-x-9)=2

The solution is x=(1+sqrt(53))/2 ,x=(1-sqrt(53))/2

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lo g_{2} (x^{2} - x - 9) = 2

x = \frac{1 + 53}{2}, x = \frac{1 - 53}{2}

Solution steps

lo g_{2} (x^{2} - x - 9) = 2

Apply log rules

x^{2} - x - 9 = 4

Solve

x^{2} - x - 9 = 4 : x = \frac{1 + 53}{2}, x = \frac{1 - 53}{2}

x = \frac{1 + 53}{2}, x = \frac{1 - 53}{2}

0 = lo g_{10} (3 - 2 x)

lo g_{10} (x) = - 1.4886

2 ln ∣ x ∣ = 2 x^{- 1}

lo g_{1} (\frac{1}{x}) = 2

lo g_{10} (x + 1) = lo g_{10} (2 x - 5)

What is the answer to log_{2}(x^2-x-9)=2 ?
The answer to log_{2}(x^2-x-9)=2 is x=(1+sqrt(53))/2 ,x=(1-sqrt(53))/2
Solve for x: log_{2}(x^2-x-9)=2
The solution is x=(1+sqrt(53))/2 ,x=(1-sqrt(53))/2