What is the answer to log_{10}(x+1)=log_{10}(2x-5) ?

The answer to log_{10}(x+1)=log_{10}(2x-5) is x=6

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log_{10}(x+1)=log_{10}(2x-5)

lo g_{10} (x + 1) = lo g_{10} (2 x - 5)

x = 6

Solution steps

lo g_{10} (x + 1) = lo g_{10} (2 x - 5)

Apply log rules

x + 1 = 2 x - 5

Solve

x + 1 = 2 x - 5 : x = 6

x = 6

Verify Solutions:

x = 6

True

The solution is

x = 6

x, 3.5 = - lo g_{10} (x)

lo g_{1} (2 x) = 3

1 - ln (2 x - 3) = 0

lo g_{\frac{1}{2}} (x^{2}) = 6

35.2 = 10 lo g_{10} (x)

What is the answer to log_{10}(x+1)=log_{10}(2x-5) ?
The answer to log_{10}(x+1)=log_{10}(2x-5) is x=6
Solve for x: log_{10}(x+1)=log_{10}(2x-5)
The solution is x=6