What is the answer to solvefor x,3.5=-log_{10}(x) ?

The answer to solvefor x,3.5=-log_{10}(x) is x= 1/(10^{3.5)}

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solvefor x,3.5=-log_{10}(x)

solve for

x, 3.5 = - lo g_{10} (x)

x = \frac{1}{1 0 ^{3.5}}

Solution steps

3.5 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

3.5 + lo g_{10} (x) = 0

Move

3.5

to the right side

lo g_{10} (x) = - 3.5

Apply log rules

x = \frac{1}{1 0 ^{3.5}}

Verify Solutions:

x = \frac{1}{1 0 ^{3.5}}

True

The solution is

x = \frac{1}{1 0 ^{3.5}}

lo g_{1} (2 x) = 3

1 - ln (2 x - 3) = 0

lo g_{\frac{1}{2}} (x^{2}) = 6

35.2 = 10 lo g_{10} (x)

x, ln (e^{- x^{2}}) = 0

What is the answer to solvefor x,3.5=-log_{10}(x) ?
The answer to solvefor x,3.5=-log_{10}(x) is x= 1/(10^{3.5)}