What is the answer to log_{1/2}(x^2)=6 ?

The answer to log_{1/2}(x^2)=6 is x= 1/8 ,x=-1/8

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log_{1/2}(x^2)=6

lo g_{\frac{1}{2}} (x^{2}) = 6

x = \frac{1}{8}, x = - \frac{1}{8}

Solution steps

lo g_{\frac{1}{2}} (x^{2}) = 6

Apply log rules

x^{2} = \frac{1}{64}

Solve

x^{2} = \frac{1}{64} : x = \frac{1}{8}, x = - \frac{1}{8}

x = \frac{1}{8}, x = - \frac{1}{8}

35.2 = 10 lo g_{10} (x)

x, ln (e^{- x^{2}}) = 0

lo g_{2} (n) = 60 \cdot 1 0^{9}

lo g_{4} ((2 x + 5)^{2}) = 2

lo g_{2} (5) (x + 2) = lo g_{5} (x)

What is the answer to log_{1/2}(x^2)=6 ?
The answer to log_{1/2}(x^2)=6 is x= 1/8 ,x=-1/8
Solve for x: log_{1/2}(x^2)=6
The solution is x= 1/8 ,x=-1/8