What is the answer to log_{4}((2x+5)^2)=2 ?

The answer to log_{4}((2x+5)^2)=2 is x=-1/2 ,x=-9/2

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log_{4}((2x+5)^2)=2

lo g_{4} ((2 x + 5)^{2}) = 2

x = - \frac{1}{2}, x = - \frac{9}{2}

Solution steps

lo g_{4} ((2 x + 5)^{2}) = 2

Apply log rules

(2 x + 5)^{2} = 16

Solve

(2 x + 5)^{2} = 16 : x = - \frac{1}{2}, x = - \frac{9}{2}

x = - \frac{1}{2}, x = - \frac{9}{2}

lo g_{2} (5) (x + 2) = lo g_{5} (x)

ln (x) - ln (4 x - 1) = ln (5)

200 = 12 lo g_{1.5} (t) + 25

lo g_{x} (91) = 2

lo g_{x} (\frac{1}{3}) = - 2

What is the answer to log_{4}((2x+5)^2)=2 ?
The answer to log_{4}((2x+5)^2)=2 is x=-1/2 ,x=-9/2
Solve for x: log_{4}((2x+5)^2)=2
The solution is x=-1/2 ,x=-9/2