What is the answer to 200=12log_{1.5}(t)+25 ?

The answer to 200=12log_{1.5}(t)+25 is t=1.5^{175/12}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

200=12log_{1.5}(t)+25

200 = 12 lo g_{1.5} (t) + 25

t = 1. 5^{\frac{175}{12}}

Decimal Notation

t = 369.82607 \dots

Solution steps

200 = 12 lo g_{1.5} (t) + 25

Switch sides

12 lo g_{1.5} (t) + 25 = 200

Move

25

to the right side

12 lo g_{1.5} (t) = 175

Divide both sides by

12

lo g_{1.5} (t) = \frac{175}{12}

Apply log rules

t = 1. 5^{\frac{175}{12}}

Verify Solutions:

t = 1. 5^{\frac{175}{12}}

True

The solution is

t = 1. 5^{\frac{175}{12}}

lo g_{x} (91) = 2

lo g_{x} (\frac{1}{3}) = - 2

lo g_{2} (2 ω + 5) - lo g_{2} (4 - ω) = 3

- ln (1 - x) = 46152

0.64 = lo g_{10} (y)

What is the answer to 200=12log_{1.5}(t)+25 ?
The answer to 200=12log_{1.5}(t)+25 is t=1.5^{175/12}
Solve for t: 200=12log_{1.5}(t)+25
The solution is t=1.5^{175/12}