What is the answer to log_{x}(1/3)=-2 ?

The answer to log_{x}(1/3)=-2 is x=e^{(ln(3))/2}

Solve for x: log_{x}(1/3)=-2

The solution is x=e^{(ln(3))/2}

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lo g_{x} (\frac{1}{3}) = - 2

x = e^{\frac{l n ( 3 )}{2}}

Solution steps

lo g_{x} (\frac{1}{3}) = - 2

Apply log rules

\frac{ln ( \frac{1}{3} )}{ln ( x )} = - 2

Multiply both sides by

ln (x)

\frac{ln ( \frac{1}{3} )}{ln ( x )} ln (x) = - 2 ln (x)

Apply log rules

x = e^{\frac{l n ( 3 )}{2}}

Verify Solutions:

x = e^{\frac{l n ( 3 )}{2}}

True

The solution is

x = e^{\frac{l n ( 3 )}{2}}

lo g_{2} (2 ω + 5) - lo g_{2} (4 - ω) = 3

- ln (1 - x) = 46152

0.64 = lo g_{10} (y)

4 ln (4 x - 3) + 8 = 16

\frac{2 ( ln ( x ) ) + 2}{x} = 0

What is the answer to log_{x}(1/3)=-2 ?
The answer to log_{x}(1/3)=-2 is x=e^{(ln(3))/2}
Solve for x: log_{x}(1/3)=-2
The solution is x=e^{(ln(3))/2}