What is the answer to 4ln(4x-3)+8=16 ?

The answer to 4ln(4x-3)+8=16 is x=(e^2+3)/4

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4ln(4x-3)+8=16

4 ln (4 x - 3) + 8 = 16

x = \frac{e ^{2} + 3}{4}

Decimal Notation

x = 2.59726 \dots

Solution steps

4 ln (4 x - 3) + 8 = 16

Move

8

to the right side

4 ln (4 x - 3) = 8

Divide both sides by

4

ln (4 x - 3) = 2

Apply log rules

4 x - 3 = e^{2}

Solve

4 x - 3 = e^{2} : x = \frac{e ^{2} + 3}{4}

x = \frac{e ^{2} + 3}{4}

Verify Solutions:

x = \frac{e ^{2} + 3}{4}

True

The solution is

x = \frac{e ^{2} + 3}{4}

\frac{2 ( ln ( x ) ) + 2}{x} = 0

x, y = 9 ln (x - 4)

ln (x^{4}) + ln (x^{2}) = 2

2 ln (x - 2) = ln (x)

lo g_{6} (lo g_{4} (x)) = 0

What is the answer to 4ln(4x-3)+8=16 ?
The answer to 4ln(4x-3)+8=16 is x=(e^2+3)/4
Solve for x: 4ln(4x-3)+8=16
The solution is x=(e^2+3)/4