What is the answer to log_{4}(x-1)=1-log_{2}(x) ?

The answer to log_{4}(x-1)=1-log_{2}(x) is x=2

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log_{4}(x-1)=1-log_{2}(x)

lo g_{4} (x - 1) = 1 - lo g_{2} (x)

x = 2

Solution steps

lo g_{4} (x - 1) = 1 - lo g_{2} (x)

Apply log rules

(x - 1) x^{2} = 4

Solve

(x - 1) x^{2} = 4 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

lo g_{10} (\frac{800}{x}) = 0.3

lo g_{2} (n + 1) = 10

1 = ln (ln (x))

5 lo g_{10} (x) = 2 lo g_{10} (x)

2 ln (x + 1) + 3 = 0

What is the answer to log_{4}(x-1)=1-log_{2}(x) ?
The answer to log_{4}(x-1)=1-log_{2}(x) is x=2
Solve for x: log_{4}(x-1)=1-log_{2}(x)
The solution is x=2