What is the answer to solvefor x,y=log_{a}(7x-b)+3 ?

The answer to solvefor x,y=log_{a}(7x-b)+3 is x=(a^{y-3}+b)/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,y=log_{a}(7x-b)+3

solve for

x, y = lo g_{a} (7 x - b) + 3

x = \frac{a ^{y - 3} + b}{7}

Solution steps

y = lo g_{a} (7 x - b) + 3

Switch sides

lo g_{a} (7 x - b) + 3 = y

Move

3

to the right side

lo g_{a} (7 x - b) = y - 3

Apply log rules

7 x - b = a^{y - 3}

Solve

7 x - b = a^{y - 3} : x = \frac{a ^{y - 3} + b}{7}

x = \frac{a ^{y - 3} + b}{7}

95 = 20 lo g_{10} (\frac{275}{x})

x, ln (y) = lo g_{4} (x)

lo g_{10} (2^{x + 1}) = 3^{x}

1 = \frac{1}{ln ( x )}

3 ln (7 x) + 7 = 19

What is the answer to solvefor x,y=log_{a}(7x-b)+3 ?
The answer to solvefor x,y=log_{a}(7x-b)+3 is x=(a^{y-3}+b)/7