What is the answer to 95=20log_{10}((275)/x) ?

The answer to 95=20log_{10}((275)/x) is x=(11)/(2^4*5^2*10^{3/4)}

Solve for x: 95=20log_{10}((275)/x)

The solution is x=(11)/(2^4*5^2*10^{3/4)}

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95 = 20 lo g_{10} (\frac{275}{x})

x = \frac{11}{2 ^{4} \cdot 5 ^{2} \cdot 1 0 ^{\frac{3}{4}}}

Decimal Notation

x = 0.00489 \dots

Solution steps

95 = 20 lo g_{10} (\frac{275}{x})

Switch sides

20 lo g_{10} (\frac{275}{x}) = 95

Divide both sides by

20

lo g_{10} (\frac{275}{x}) = \frac{19}{4}

Apply log rules

\frac{275}{x} = 1 0^{\frac{19}{4}}

Multiply both sides by

x

\frac{275}{x} x = 1 0^{\frac{19}{4}} x

Simplify

1 0^{\frac{19}{4}} x : 1 0^{4 + \frac{3}{4}} x

275 = 1 0^{4 + \frac{3}{4}} x

Solve

275 = 1 0^{4 + \frac{3}{4}} x : x = \frac{11}{2 ^{4} \cdot 5 ^{2} \cdot 1 0 ^{\frac{3}{4}}}

x = \frac{11}{2 ^{4} \cdot 5 ^{2} \cdot 1 0 ^{\frac{3}{4}}}

Verify Solutions:

x = \frac{11}{2 ^{4} \cdot 5 ^{2} \cdot 1 0 ^{\frac{3}{4}}}

True

The solution is

x = \frac{11}{2 ^{4} \cdot 5 ^{2} \cdot 1 0 ^{\frac{3}{4}}}

x, ln (y) = lo g_{4} (x)

lo g_{10} (2^{x + 1}) = 3^{x}

1 = \frac{1}{ln ( x )}

3 ln (7 x) + 7 = 19

lo g_{3} (x + 9) + 4 = 0

What is the answer to 95=20log_{10}((275)/x) ?
The answer to 95=20log_{10}((275)/x) is x=(11)/(2^4*5^2*10^{3/4)}
Solve for x: 95=20log_{10}((275)/x)
The solution is x=(11)/(2^4*5^2*10^{3/4)}