What is the answer to log_{3}(x+9)+4=0 ?

The answer to log_{3}(x+9)+4=0 is x=-728/81

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log_{3}(x+9)+4=0

lo g_{3} (x + 9) + 4 = 0

x = - \frac{728}{81}

Solution steps

lo g_{3} (x + 9) + 4 = 0

Move

4

to the right side

lo g_{3} (x + 9) = - 4

Apply log rules

x + 9 = \frac{1}{81}

Solve

x + 9 = \frac{1}{81} : x = - \frac{728}{81}

x = - \frac{728}{81}

Verify Solutions:

x = - \frac{728}{81}

True

The solution is

x = - \frac{728}{81}

lo g_{3} (lo g_{5} (x)) = 2

x, y = ln (\frac{1}{2} x)

lo g_{4} (9) - lo g_{4} (x - 3) = 1

lo g_{2} (x + 16) + lo g_{2} (x + 2) = 8

7 ln (2 x + 5) = 8

What is the answer to log_{3}(x+9)+4=0 ?
The answer to log_{3}(x+9)+4=0 is x=-728/81
Solve for x: log_{3}(x+9)+4=0
The solution is x=-728/81