What is the answer to log_{4}(9)-log_{4}(x-3)=1 ?

The answer to log_{4}(9)-log_{4}(x-3)=1 is x= 21/4

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log_{4}(9)-log_{4}(x-3)=1

lo g_{4} (9) - lo g_{4} (x - 3) = 1

x = \frac{21}{4}

Solution steps

lo g_{4} (9) - lo g_{4} (x - 3) = 1

Move

lo g_{4} (9)

to the right side

- lo g_{4} (x - 3) = 1 - lo g_{4} (9)

Divide both sides by

- 1

lo g_{4} (x - 3) = - 1 + lo g_{4} (9)

Apply log rules

x - 3 = \frac{9}{4}

Solve

x - 3 = \frac{9}{4} : x = \frac{21}{4}

x = \frac{21}{4}

Verify Solutions:

x = \frac{21}{4}

True

The solution is

x = \frac{21}{4}

lo g_{2} (x + 16) + lo g_{2} (x + 2) = 8

7 ln (2 x + 5) = 8

(ln (x)) (ln (x)) = 2 (ln (x))

lo g_{10} (3 x) = 0.85

lo g_{3} (3^{x^{2} - 2 x}) = 0

What is the answer to log_{4}(9)-log_{4}(x-3)=1 ?
The answer to log_{4}(9)-log_{4}(x-3)=1 is x= 21/4
Solve for x: log_{4}(9)-log_{4}(x-3)=1
The solution is x= 21/4