What is the answer to 3^{1-log_{9}(x)}=x ?

The answer to 3^{1-log_{9}(x)}=x is x=\sqrt[3]{9}

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3^{1-log_{9}(x)}=x

3^{1 - l o g_{9} (x)} = x

Decimal Notation

x = 2.08008 \dots

Solution steps

3^{1 - l o g_{9} (x)} = x

Apply log rules

Verify Solutions:

True

The solution is

lo g_{a} (x^{c}) = c lo g_{a} (x)

4^{2} \cdot lo g_{4} (x + 2) = 32

- 3.5 = 5 lo g_{10} (x) - 5

lo g_{- 2 x - 2} (3 x^{2} - 4 x - 16) = 2

- \frac{ln ( - 10 ( 0 ) ^{2} - x )}{4} = 0

What is the answer to 3^{1-log_{9}(x)}=x ?
The answer to 3^{1-log_{9}(x)}=x is x=\sqrt[3]{9}
Solve for x: 3^{1-log_{9}(x)}=x
The solution is x=\sqrt[3]{9}