What is the answer to 14-12.05=-log_{10}(x) ?

The answer to 14-12.05=-log_{10}(x) is x= 1/(10^{1.95)}

Solve for x: 14-12.05=-log_{10}(x)

The solution is x= 1/(10^{1.95)}

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14 - 12.05 = - lo g_{10} (x)

x = \frac{1}{1 0 ^{1.95}}

Decimal Notation

x = 0.01122 \dots

Solution steps

14 - 12.05 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

lo g_{10} (x) + 1.95 = 0

Move

1.95

to the right side

lo g_{10} (x) = - 1.95

Apply log rules

x = \frac{1}{1 0 ^{1.95}}

Verify Solutions:

x = \frac{1}{1 0 ^{1.95}}

True

The solution is

x = \frac{1}{1 0 ^{1.95}}

lo g_{4} (2 - x) = lo g_{4} (- 5 x - 18)

x, 2 x - 1 = e^{l n (x) 2}

lo g_{10} (x) = 0.1445

x, ln (x) = 0.19 y + 1.9

2 \cdot ln (x) = 6.8

What is the answer to 14-12.05=-log_{10}(x) ?
The answer to 14-12.05=-log_{10}(x) is x= 1/(10^{1.95)}
Solve for x: 14-12.05=-log_{10}(x)
The solution is x= 1/(10^{1.95)}