What is the answer to log_{4}(2-x)=log_{4}(-5x-18) ?

The answer to log_{4}(2-x)=log_{4}(-5x-18) is x=-5

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log_{4}(2-x)=log_{4}(-5x-18)

lo g_{4} (2 - x) = lo g_{4} (- 5 x - 18)

x = - 5

Solution steps

lo g_{4} (2 - x) = lo g_{4} (- 5 x - 18)

Apply log rules

2 - x = - 5 x - 18

Solve

2 - x = - 5 x - 18 : x = - 5

x = - 5

Verify Solutions:

x = - 5

True

The solution is

x = - 5

x, 2 x - 1 = e^{l n (x) 2}

lo g_{10} (x) = 0.1445

x, ln (x) = 0.19 y + 1.9

2 \cdot ln (x) = 6.8

5 = lo g_{e} (t + e^{2})

What is the answer to log_{4}(2-x)=log_{4}(-5x-18) ?
The answer to log_{4}(2-x)=log_{4}(-5x-18) is x=-5
Solve for x: log_{4}(2-x)=log_{4}(-5x-18)
The solution is x=-5