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Popular >

5=log_{e}(t+e^2)

Solution

5 = lo g_{e} (t + e^{2})

Solution

t = e^{5} - e^{2}

+1

Decimal Notation

t = 141.02410 \dots

Solution steps

5 = lo g_{e} (t + e^{2})

Apply log rules

e^{5} = t + e^{2}

Solve

e^{5} = t + e^{2} : t = e^{5} - e^{2}

t = e^{5} - e^{2}

Popular Examples

ln(y)=3.86+0.8961*7.5

ln (y) = 3.86 + 0.8961 \cdot 7.5

log_{2}(x)+log_{2}(x-3)=1

lo g_{2} (x) + lo g_{2} (x - 3) = 1

2ln(x-5)+ln(x+8)=3ln(x)

2 ln (x - 5) + ln (x + 8) = 3 ln (x)

log_{2}(x)+log_{2}(x-3)=3

lo g_{2} (x) + lo g_{2} (x - 3) = 3

y x = y ln (cy (x))

Frequently Asked Questions (FAQ)

What is the answer to 5=log_{e}(t+e^2) ?
The answer to 5=log_{e}(t+e^2) is t=e^5-e^2