What is the answer to 90=10log_{10}(I*10^{12}) ?

The answer to 90=10log_{10}(I*10^{12}) is I=(1000000000)/(10^{12)}

Solve for I: 90=10log_{10}(I*10^{12})

The solution is I=(1000000000)/(10^{12)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

90 = 10 lo g_{10} (I \cdot 1 0^{12})

I = \frac{1000000000}{1 0 ^{12}}

Decimal Notation

I = 0.001

Solution steps

90 = 10 lo g_{10} (I \cdot 1 0^{12})

Switch sides

10 lo g_{10} (I 1 0^{12}) = 90

Divide both sides by

10

lo g_{10} (I 1 0^{12}) = 9

Apply log rules

I \cdot 1 0^{12} = 1000000000

Solve

I \cdot 1 0^{12} = 1000000000 : I = \frac{1000000000}{1 0 ^{12}}

I = \frac{1000000000}{1 0 ^{12}}

Verify Solutions:

I = \frac{1000000000}{1 0 ^{12}}

True

The solution is

I = \frac{1000000000}{1 0 ^{12}}

- 17.5 = 10 lo g_{10} (\frac{x}{1})

lo g_{5} (x^{2}) = 3.1

lo g_{x + 1} (64) = 2

ln (x) = 10.09876582

ln (x) = \frac{1}{e}

What is the answer to 90=10log_{10}(I*10^{12}) ?
The answer to 90=10log_{10}(I*10^{12}) is I=(1000000000)/(10^{12)}
Solve for I: 90=10log_{10}(I*10^{12})
The solution is I=(1000000000)/(10^{12)}