What is the answer to solvefor a,log_{b}(2a)=4 ?

The answer to solvefor a,log_{b}(2a)=4 is a=(b^4)/2

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solvefor a,log_{b}(2a)=4

solve for

a, lo g_{b} (2 a) = 4

a = \frac{b ^{4}}{2}

Solution steps

lo g_{b} (2 a) = 4

Apply log rules

2 a = b^{4}

Solve

2 a = b^{4} : a = \frac{b ^{4}}{2}

a = \frac{b ^{4}}{2}

y, lo g_{10} (x y) = y

x = ln (x + 1)

\frac{x}{4} = lo g_{2} (x)

x, 0.3 = - lo g_{10} (x)

ln (4 x - 3) = ln (9) - ln (x - 3)

What is the answer to solvefor a,log_{b}(2a)=4 ?
The answer to solvefor a,log_{b}(2a)=4 is a=(b^4)/2