What is the answer to log_{10}(x)=-1.22 ?

The answer to log_{10}(x)=-1.22 is x= 1/(10^{1.22)}

Solve for x: log_{10}(x)=-1.22

The solution is x= 1/(10^{1.22)}

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lo g_{10} (x) = - 1.22

x = \frac{1}{1 0 ^{1.22}}

Solution steps

lo g_{10} (x) = - 1.22

Apply log rules

x = \frac{1}{1 0 ^{1.22}}

8 = 4 lo g_{10} (\frac{t - 2}{20})

lo g_{2} (x - 1) - lo g_{2} (x + 2) = 1

\frac{1}{2} = lo g_{x} (2)

lo g_{100} (x) = 1.5

lo g_{\frac{1}{4}} (x) = 0

What is the answer to log_{10}(x)=-1.22 ?
The answer to log_{10}(x)=-1.22 is x= 1/(10^{1.22)}
Solve for x: log_{10}(x)=-1.22
The solution is x= 1/(10^{1.22)}