What is the answer to log_{10}(x-1)+2=2 ?

The answer to log_{10}(x-1)+2=2 is x=2

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log_{10}(x-1)+2=2

lo g_{10} (x - 1) + 2 = 2

x = 2

Solution steps

lo g_{10} (x - 1) + 2 = 2

Subtract

2

from both sides

lo g_{10} (x - 1) + 2 - 2 = 2 - 2

Simplify

lo g_{10} (x - 1) = 0

Apply log rules

x - 1 = 1

Solve

x - 1 = 1 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

lo g_{2} (x + 2) = 3 + lo g_{2} (1 - x)

ln (t) = 1.56 + 0.82 \cdot ln (34)

2 lo g_{10} (x) - lo g_{10} (5 x) = 1

x 4 ln (x) - 8 = 12

x - 8 + lo g_{2} (x + 6) = - 5

What is the answer to log_{10}(x-1)+2=2 ?
The answer to log_{10}(x-1)+2=2 is x=2
Solve for x: log_{10}(x-1)+2=2
The solution is x=2